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N = 5 - (0 + 1/2 * 8) = 1 |
O = 6 - (6 + 1/2 * 2) = -1 |
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H = 1 - (0 + 1/2 * 2) = 0 |
4. Determine formal charge.
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N = 5 - (0 + 1/2 * 8) = 1 |
O = 6 - (6 + 1/2 * 2) = -1 |
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H = 1 - (0 + 1/2 * 2) = 0 |
H3NO does not exist as a stable molecule, but a very similar compound, (CH3)3NO, does exist. Because there is a separation of + and - charge, (CH3)3NO is a very reactive molecule. (CH3)3NO is very good at adding one O atom to other compounds. (Can you draw (CH3)3NO ?)
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done |